There is one small problem to your logic. 0.4 psi may not sound big with a 1" pipe but when you need to exert that same amount of pressure evenly through two or more 15 m diameter fans then it becomes a big problem.
That is about 618,110Kg of air needed to be displaced per second.
I wonder how strong that fans requires to be and how much fuel it would take to run it?
Sigh, since I work in metric and talk in imperial, its gonna be a pain... but here goes
pressure required 2.74 Pa.. lets say 3 Pa
Lets assume that the hover craft hovers 0.3 m for leakage. 57m X 25.6 = a perimeter of 165.2 m; with a height of 0.3 that is a leakage area of 49.56 m2, say 50 m2
Bernoulli's Equation... no height change, dp = 1/2*rho*V2
dp = 3 Pa
Rho = 1.225 kg/m3 @ sea level (literally)
therefore V = 2.21 m/s leakage
Q = Volume lost = 2.21 m/s X 50 m2 = 110.5 m3/s
Assume 50% rotor efficiency, Eff.
P (power) = (dp X Q) / Eff
P = 663 W
Now this is theoretical; no waves, flat surface, no rough losses... so lets say reality will be like 10X more energy so 6.6 kW? or ~2hp ? the Zubr can fly up to around 2 m on an air cushion.. so the fan is definitely much bigger and safety/failure backup..
The Zubr, have 5x gas turbine, 11,836 HP each, 2 is for levitation, i suppose one duty, one standby. gas turbine to electicity... around 25% efficiency, ~3000 HP; mechanical efficiency is like.. 70% and typical design safety is 200-300% so around 700-1000 HP is used for levitating the craft.
point in case is only that it doesn't take a very big fan to levitate a hovercraft;
Some 15 years ago, I worked on a school project for a 2 person hover craft, the whole thing with forward propulsion was on a 2 hp motor and it easily went 10-20 km/hr. fun days