In general I agree, but as long as your layered defence still gives an incoming missile X% of chance of getting through you will still run out of luck sometime.
In an oversimplified "russian roulette style" model that just takes a probability of catching one missile a time and repeats it multiple times your chance of not getting hit decreases with the number of tries:
Take a probability of 98% of intercepting a missile, catching 10 rounds has a probability of 82%, 20 rounds 67%, 30 rounds 55%, ...
With 95% it would be 60% for 10 rounds, 36% for 20 rounds, 21% for 30 rounds.
Carrying enough interceptors to potentially intercept 100 incoming missiles would be asking for a lot of luck (or trusting your engineers to give you near 100% intercept chances).
98% of intercepting a missile could be very optimistic depending on the missile. RAM is credited with >0.95 (presumably against missiles), while the S-400 is quoted with 0.7 against Harpoon-type missiles (i.e. subsonic, non-maneuvering, non-stealthy, non-crossing shot).
Assuming the HHQ-9 has a similar Pk to the S-400, then we can play out an interesting mental scenario: If the 055 has 128 cells and is fitting for maximal AAW with minimal consideration for ASW and ASuW and no LACMs, you could conceivably have a very large SAM loadout of 88 HHQ-9s and 64 DK-10As in 16 cells (along with the 8 ASW missiles and 16 antiship missiles). I can't find any Pk vs missile for the ESSM right now but let's assume it is in between S-400 and RAM, like 85%, and that the DK-10A is also similar. So vs vanilla missile Pks will be: HHQ-9 = 0.7, DK-10A = 0.85, HHQ-10 = 0.95. Let's also assume BTW that the 055 has overhead AEW/C support so that it can begin to attack inbound missiles at the HHQ-9's maximum range instead of inside the 055's radar horizon, which means that a single HHQ-9 can be assigned per target, or in the case of more than 44 inbound targets, a single HHQ-9 will HAVE to be assigned to some, most or all targets. For example, out of a hypothetical 100 inbound targets engaged initially by the HHQ-9s, all 88 would be assigned to individual targets. We also have to assign missile failures; let's say it's 4 missiles or 4.5% failure rate, which seems reasonable to me. Out of 84 targets attacked in the first round, about 25 statistically will get through, and with 16 targets unchallenged, a total of 41 will make it through to the next round, with all 88 HHQ-9s expended. The next layer of defense starts possibly at around 50km, depending on DK-10A's range. At this range there is still time to attack and reassess, so only 1 DK-10A will be launched per target. Out of 41 targets engaged in the second round, 2 DK-10A's will fail (similar failure rate of 4.9%). Out of 39 targets engaged, 6 will survive. Add the 2 unchallenged targets, a total of 8 will slip through to the third round. Round 3 will leave no time for reassessment, so 2 DK-10s will be assigned to each target for a total of 16 DK-10As. Roughly 1 target will fail to get hit, leaving 1 target for round 4. 2 HHQ-10s will be assigned to this target. Assuming this does the trick, after the initial wave of 100 inbound ASCMs all 100 have been downed, all 88 HHQ-9s have been expended, 57 of 64 DK-10As have been expended, and 2 of 24 HHQ-10s have been expended.
If you do this same mental exercise but eliminate the overhead AEW/C and instead start the engagement under conditions of complete surprise at 30km (radar horizon), those 100 inbound missiles will impose significantly more risk to the 055. 88 HHQ-9s would be doubly assigned to 44 targets; with 4 failures, meaning 4 targets would be engaged by only a single HHQ-9, with 1 of the 4 getting through; of the 40 engaged by 2 HHQ-9s, 4 would likely get through (Pm = 0.3 x 0.3 = 0.09), for a total of 5 targets slipping through after engagement by HHQ-9s. All 64 DK-10s would also be expended, with 48 targets having only one DK-10A assigned and 8 targets having 2 DK-10A assigned. Of the 48 targeted, about 2 would fail; of the 46 engaged, 7 would slip through, for a total of 9 targets slipping through. Of the 8 targets attacked by 16 DK-10As, probably none would slip through. So of the 56 targets attacked by 64 DK-10As, 9 would slip through. So a total of 14 targets would make it to the second round, which is now about at point blank range. 4 targets would each be assigned a single HHQ-10 while 10 targets will be assigned 2 HHQ-10s each. 1 HHQ-10 out of 24 will fail, and it will likely be in the double target group. Despite this, given the high Pk of the HHQ-10 it is likely all 14 will be destroyed by the HHQ-10 launcher. At this point all 100 of the targets will still have been shot down, but every last air defense missile in the 055's inventory is now expended, leaving chaff, decoys, ECM, and the 1130 as all that stands between the next swarm of missiles and the bottom of the ocean. This also assumes a maximal AAW loadout, when in general practice a more balanced arsenal is far more likely, with some mixture of BMD/anti-sat missiles, LACMs, and possibly additional ASW and antiship missiles as a more typical loadout for the 055.
And of course we have not talked about missile control channels. Can the 055 and the overhead AEW/C control all 88 HHQ-9s simultaneously in mid flight? I think I read somewhere long ago that the SPY-1D can control somewhere in the neighborhood of two dozen missiles simultaneously. The APAR can allegedly control 32 simultaneously. I guess it is possible that the Type 346B is a significant advancement over these systems and can control many more engagements simultaneously. The answer becomes far more unlikely, however, if we are talking about all 152 (88+64) missiles in the air simultaneously, though the notional DK-10A is allegedly active-guided and may not actually need to take up a control channel for as long as an SARH-guided missile.