Hendrik_2000
Lieutenant General
Exactly let do the calc to get the feel By the time the warhead enter the atmosphere it roughly 100km=62miles. Now mach 10 warhead speeding at 7672miles/hr
So the Carrier has only (62/7672) X60 minutes=0.48 minute to travel. Now how fast is the ship say 30 knots=34.5 miles /hour=50 ft/second X 0.48 X 60=1440 feet=0.27 mile Now calculate the area piXRsquare= 3.14 X 0.27 X0.27=0.228 square miles of kill zone. Calculate the angle = power-1( tan(0.27/62))=0.24 degree deviation from 90 degree straight down. So the warhead only has to make 0.24 degree adjustment once the sensor detect the ship
![1598918774701.png 1598918774701.png](https://www.sinodefenceforum.com/data/attachments/56/56628-e53eb584899a2c4dee2b4654f668128e.jpg)
So the Carrier has only (62/7672) X60 minutes=0.48 minute to travel. Now how fast is the ship say 30 knots=34.5 miles /hour=50 ft/second X 0.48 X 60=1440 feet=0.27 mile Now calculate the area piXRsquare= 3.14 X 0.27 X0.27=0.228 square miles of kill zone. Calculate the angle = power-1( tan(0.27/62))=0.24 degree deviation from 90 degree straight down. So the warhead only has to make 0.24 degree adjustment once the sensor detect the ship
![1598918774701.png 1598918774701.png](https://www.sinodefenceforum.com/data/attachments/56/56628-e53eb584899a2c4dee2b4654f668128e.jpg)
Last edited: