Engineer
Major
Re: J-20 The New Generation Fighter Thread IV
Since I am much more knowledgeable than you are, let me teach you an important concept about the cross product. A cross product must be perpendicular to the original two vectors:
So, pitch moment as a result of thrust vectoring must be perpendicular to direction of the vectored thrust. Even says I am correct. Here is the proof:
The title said "pitch rotation about Y". The 1 within the matrix occupies the middle column, which can only be multiplied by Y. The Y axis lies in the span wise direction, so you obviously don't know what a pitch moment is when you claimed it is an "up and down" vector. You have even debunked your own claim when you said this:
I said that because no where did I say "an aircraft is a wrench". It is that simple. You simply can't handle how right I am, since you are now making stuffs up and can't form a coherent sentence. ROFL!You have said that according to your definition of the cross product and pitch and more important is obvious you do not understand the equation since you do not understand this detail
You keep pathetically going in circles, yet you are unable to prove your little accusation of me claiming "an aircraft is a wrench". Meanwhile, your betrays your own ignorance on linear algebra and physics.If products of inertia are zero, (x, y, z)
are principal axes --->"
• All rigid bodies have a set of principal
axes"
source
You do not understand the Matrix and it is obvious, since you do not understand what is written in the same source.
Your definition of cross product and pitch were like a wrench, however you do not understand the concept of vector and it is obvious since the products of inertia are zero at the Y axis and the pitch matrix shows the same with the 0s
Since I am much more knowledgeable than you are, let me teach you an important concept about the cross product. A cross product must be perpendicular to the original two vectors:
Here, uxv is always perpendicular to both u and v, with the orientation determined by the right-hand rule.
So, pitch moment as a result of thrust vectoring must be perpendicular to direction of the vectored thrust. Even says I am correct. Here is the proof:
The title said "pitch rotation about Y". The 1 within the matrix occupies the middle column, which can only be multiplied by Y. The Y axis lies in the span wise direction, so you obviously don't know what a pitch moment is when you claimed it is an "up and down" vector. You have even debunked your own claim when you said this:
X and Z have sines and cosines while Y doesn't, meaning the rotation is about Y. ROFL!the pitch matrix only have sines and cosines for X and Z and in the equations.
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