Skywatcher
Captain
Re: J-20 The New Generation Fighter Thread IV
The last few percentages (correct syntax) are important in aero-engineering and other high tech, high stakes fields, even for purposes of prediction.
So shaping reduces the RCS from 10m2 to 1m2. Then, RAM reduces the 1m2 down to 0.01 m2. But with a 10% miscalculation of the RAM effects, then you get a RCS of about 0.1m2.
That's a tenfold increase!
I am talking about miscalculating the effects of the RAM, not the RCS as a whole. Is that clear, even to you?
Thanks to the modern technology of datalinks and midcourse correction, Fighter B can first fire its BVRAAM in the direction of Fighter A. As the BVRAAM goes on its merry way to Fighter A, Fighter B's radar can acquire a reasonably definitive lock on Fighter A and issue corrections to its BVRAAM. Eventually, the BVRAAM will get close enough to Fighter A to pick it up with its own sensors, and Fighter B can go off to attend other tasks.
And Fighter B then will still most likely be the first to establish a lock in any case.
Depends on the BVRAAM, some of the modern ones accelerate very quickly (upwards of 28-30Gs if the manufacturers are to be believed) and go past Mach 4, so Mach 4 is a decent average (we can settle on an initial average of Mach 3.5 if that makes you happy).
Fighter B doesn't have to maintain his heading all the way into WVR territory. As soon as the no escape zone of its BVRAAM is great enough, he can break off contact as soon as the BVRAAM can lock onto Fighter A on its own.
Let's say that WVR is about 20km (Wiki has it at 30km, but most WVRAAM don't have that sort of range).
It will take forty seconds for Fighter A and B to get within 20 km of each other (since at Mach 1.5, it will take each Fighter that amount of time to travel 20 km).
But getting WVR for Fighter A is a moot point. Because in that time, the BVRAAM will have traveled 52km at Mach 4.
My ally said that. If you haven't noticed, him (I'm assuming you're referring to a male) and I are different persons.) Sounds like a pretty big misrepresentation (don't think I need to go to OED for that).Firstly, I have explained in one of my previous posts that in post #1869, your ally expected every single details to be replicated, which would result in a perfect model. Secondly, you are making a big deal out of any deviation in the last few percents of RCS estimation. Anyone who is not expecting perfection will find that small of a deviation as being acceptable.
The last few percentages (correct syntax) are important in aero-engineering and other high tech, high stakes fields, even for purposes of prediction.
You used the word "absolute" to declare that you could predict how technology behaves. That means you can predict how the technology can behave "without limit". In order have the limitless "absolute prediction", you will have to have that perfect model that you obsess over.Nope. First of all, your definition has nothing to do with the statement "you can absolutely predict how the other guy's technology will behave". Secondly, your interpretation of the dictionary was entirely opposite to what the dictionary is saying. There is no such requirement of "using the exact same pieces of technology", not even according to the dictionary, as the meaning is entirely your invention.
If you want to understand what the RAM is exactly contribute to the the RCS reduction, you'd better know what that piece of technology is.Firstly, estimating RCS does not require all the fighters to use the same pieces of technologies. We are talking about estimates, not exact values. Second, there exist expertise for China to drawn upon, irrespectively of whether they are spare. What you have brought up here is non-issue.
I believe it was you who suggested that Chinese engineers could have misunderestimated the RAM effects by 60% (if that post on the J-20 thread hasn't been deleted yet).If you are wondering where I get the 90% figure from when I said you are portraying Chinese experts as a bunch of amatures, your above post would be it.
The effect of RCS reduction is logarithmic, as you pointed out earlier.Previously, we have learned that 90~95% of the stealth comes from shaping. This puts the remaining 5~10% as effects from RAM. In other words, by assuming there to be a 10% miscalculation in RCS estimation, your thought experiment assumed the Chinese engineers to be so incompetent that their estimations would miss the effects from RAM entirely. Your experiment isn't realistic to begin with. Additionally, there are three other problems.
So shaping reduces the RCS from 10m2 to 1m2. Then, RAM reduces the 1m2 down to 0.01 m2. But with a 10% miscalculation of the RAM effects, then you get a RCS of about 0.1m2.
That's a tenfold increase!
I am talking about miscalculating the effects of the RAM, not the RCS as a whole. Is that clear, even to you?
That would be true... for Vietnam War era technology.First, there is a difference between detection and lock. This was brought up very early on when the scans from a Chinese paper was posted. As opposed to your imagination, your fighter B will not enjoy the advantage of launching any missile right after detection.
Thanks to the modern technology of datalinks and midcourse correction, Fighter B can first fire its BVRAAM in the direction of Fighter A. As the BVRAAM goes on its merry way to Fighter A, Fighter B's radar can acquire a reasonably definitive lock on Fighter A and issue corrections to its BVRAAM. Eventually, the BVRAAM will get close enough to Fighter A to pick it up with its own sensors, and Fighter B can go off to attend other tasks.
And Fighter B then will still most likely be the first to establish a lock in any case.
Second, BVRAAM does not have an initial speed of 4900 km/h. The missile has to accelerate, so the actual range traveled by the missile would actually be less than 8 km.
Depends on the BVRAAM, some of the modern ones accelerate very quickly (upwards of 28-30Gs if the manufacturers are to be believed) and go past Mach 4, so Mach 4 is a decent average (we can settle on an initial average of Mach 3.5 if that makes you happy).
It might interest you to know that not all maneuvering is turning to present a portside view of the aircraft to the opponent. Just a thought.Thirdly, a fighter cannot maintain 54km away while presenting the least RCS simultaneously. If Fighter B turns, RCS would not be minimal. If Fighter B maintains its heading, the distance will close rapidly and the engagement will become WVR.
Fighter B doesn't have to maintain his heading all the way into WVR territory. As soon as the no escape zone of its BVRAAM is great enough, he can break off contact as soon as the BVRAAM can lock onto Fighter A on its own.
Let's say that WVR is about 20km (Wiki has it at 30km, but most WVRAAM don't have that sort of range).
It will take forty seconds for Fighter A and B to get within 20 km of each other (since at Mach 1.5, it will take each Fighter that amount of time to travel 20 km).
But getting WVR for Fighter A is a moot point. Because in that time, the BVRAAM will have traveled 52km at Mach 4.