Quickie
Colonel
That diagram has PL-21 in a 45 degree 3D view. Look at its tail vs front.
Yes, I've notised that. I used the middle of PL-21 to estimate the diameter.
That diagram has PL-21 in a 45 degree 3D view. Look at its tail vs front.
It can't be shorter but by the look of pl-21's configuration it cannot be significantly larger either...
Yes, I've notised that. I used the middle of PL-21 to estimate the diameter.
Looks like it is about the PL-12D. A lot of chatter on the Chinese boards about it.
the first one is just your typical Chinese newspaper that quotes some American source, most likely JDW or Richard Fisher or Carlo Kopp or one of these people. I don't take that too seriously. But there is no question that China has quite a robust AAM program going. We will have to wait and see as usual.
Use the middle for thickness, but you also need to multiple the length by about 1.4 (assuming the picture is a 45 degree view).
I didn't see your reply earlier. If the length is scaled to 1.4 times, the thickness at the front of the missile should be used instead
There is a perspective issue. It depends on how far the photo was taken.
If the photo was taken far away, then it doesn't matter because the front and rear won't be that much different.
However, that photo was taken from close distance. So you need to use the middle section's width, and 1.4x of the length. If you use the front width, then you probably will need to x2.0+.
You can use a tube and digital camera and do some experiment and you will see what I mean.
Scaling the missile length to 1.4 times (from a 45 degree angle of view) is actually bringing the end of the missile nearer to the camera to the same distance as that from the front of the missile to the camera. If the middle width of the missile is to be used, the change in magnification along the length of the missile will have to be calculated. Assuming magnification along the whole length of missile is 2.5 times, the middle width will have to multiply by 2.5/1.75 times. The largest diameter of the missile in the image is actually at 80% (or thereabout) of the whole length of the missile. For this reason, it will need to be multiply by 2.5/2.2 to get everything to scale if a perpendicular view is to be desired.
It is only 1.4X of width if the photo is taken with telephoto lens. But with tele, the front and end will appear about the same thickness.
With normal lens, if you keep the front at the same position and rotate the end closer, it will be much more than 1.4X on the photo. Same, if you keep the end at the same position, and rotate the front farther, it will be much less than 1.4X.
We are talking about photography. Best way is to experiment it yourself. Take a picture of a pen at 45 degrees, then rotate. you will see what I mean.