Martian
Senior Member
Microwaves, Avogadro's number, and RAM
I do not agree with you. You know that a glass of water is heated in a microwave oven by absorbing microwave radiation. Looking at the chart of radar bands in the microwave energy range, you can see that many radar bands lie at or near the frequency of 2.45 gigahertz (e.g. S-band) for microwave ovens. Aside from the dust particles, soot, hail, clouds, air molecules, etc., we know that water droplets in the air will absorb microwave energy.
Chart of radar bands in the microwave energy range
"A microwave oven works by passing non-ionizing microwave radiation, usually at a frequency of 2.45 gigahertz (GHz)—a wavelength of 122 millimetres (4.80 in)—through the food. Microwave radiation is between common radio and infrared frequencies. Water, fat, and other substances in the food absorb energy from the microwaves in a process called dielectric heating."
----------
I do not agree with you on your analogy for photons. I just don't feel like going through a long analysis and discussing Avogadro's number (e.g. 6.022x10^23 molecules/mole). It should be obvious to you that the microwaves from a microwave oven are not having problems interacting with water molecules.
----------
I do not agree with you. The Russian T-50 has exposed engine compressor blades. There are other items on an aircraft that cannot be covered with RAM. The Russian T-50 also has vents and gaps that cannot be covered with RAM. My point is that RAM is only one important aspect of stealth.
To rise to the exquisite level of F-22 or J-20 stealth, it requires a full-spectrum stealth design (e.g. continuous curvature, serpentine air-inlets, DSI, canted air-intakes, planform alignment, frameless cockpit canopy, smooth uncluttered surfaces, well-integrated air-inlet and fuselage junction, extensive saw-toothed doors, hatches, and engine-fuselage interfaces, etc.). Stealth is a lot more than just RAM.
Egads, no! Even an incredibly powerful radar is not vapourizing water droplets! Never mind that most of the water is already in the form of vapour anyway - you're not moving the water droplets either.
Photons interact with matter at the atomic level, and at that level even solid objects are mostly empty space. Shooting a photon through the atmosphere is sort of like shooting a spaceship through the solar system. You will occasionally hit something, but you have to be pretty unlucky.
I do not agree with you. You know that a glass of water is heated in a microwave oven by absorbing microwave radiation. Looking at the chart of radar bands in the microwave energy range, you can see that many radar bands lie at or near the frequency of 2.45 gigahertz (e.g. S-band) for microwave ovens. Aside from the dust particles, soot, hail, clouds, air molecules, etc., we know that water droplets in the air will absorb microwave energy.

Chart of radar bands in the microwave energy range
"A microwave oven works by passing non-ionizing microwave radiation, usually at a frequency of 2.45 gigahertz (GHz)—a wavelength of 122 millimetres (4.80 in)—through the food. Microwave radiation is between common radio and infrared frequencies. Water, fat, and other substances in the food absorb energy from the microwaves in a process called dielectric heating."
----------
I do not agree with you on your analogy for photons. I just don't feel like going through a long analysis and discussing Avogadro's number (e.g. 6.022x10^23 molecules/mole). It should be obvious to you that the microwaves from a microwave oven are not having problems interacting with water molecules.
----------
No offense but when you apply the amount of EM reduction from the claimed RAM figure, then virtually no shape other than perhaps corner reflectors would amount to anything detectable.
E.g., to start it simple, a metal ball(1m radius) has an rcs of 1m^2, if you apply ram, taking away even 99.684% of the EM reflected energy, you'll get an RCS of 0.00316m^2, that is on par with the F-35, with a what is possibly the worst stealth shape anyone can make(sphere).
I do not agree with you. The Russian T-50 has exposed engine compressor blades. There are other items on an aircraft that cannot be covered with RAM. The Russian T-50 also has vents and gaps that cannot be covered with RAM. My point is that RAM is only one important aspect of stealth.
To rise to the exquisite level of F-22 or J-20 stealth, it requires a full-spectrum stealth design (e.g. continuous curvature, serpentine air-inlets, DSI, canted air-intakes, planform alignment, frameless cockpit canopy, smooth uncluttered surfaces, well-integrated air-inlet and fuselage junction, extensive saw-toothed doors, hatches, and engine-fuselage interfaces, etc.). Stealth is a lot more than just RAM.
Last edited: