Yes, a bigger dish does collect more energy and allow you to detect further objects. But making a bigger dish output the same amount of power as a smaller dish does not change the signal response at a distance as you originally claimed.
Not sure what you're trying to say.
But signal intensity at the source does determine the signal intensity at the distance according to the inverse square law.
Check out the link
.
""The
intensity of
radio waves over
distance obeys the inverse-square law, which states that
intensity is inversly proportional to the square of the
distance from a source. Think of it this way: double the
distance, and you get four times less power. ... Notice how steeply the
intensity drops off at each point.""
Alright, lets look at your logic here. You're saying that only the initial signal intensity (W/m^2) matters, not the emission area (m^2)? Think carefully about how ridiculous that is. You're proposing that 100 flashlights in a grid are just as effective at spotting an object far away in the dark as 1 flashlight is. They have the same inital signal intensity after all!
What are you talking about? Having 100 flashlights together in a small place ("in a grid" as you say) will roughly have 100 times the intensity of 1 lightbulb.
Okay to help you understand. Imagine the radio telescope as a car headlight with the lightbulb at the focal point of the reflecting parabolic dish. Increasing the size of the parabolic disc of the car headlight while keeping the same lightbulb (analogous to keeping the same amount of radio signal power) will increase the area of the lighted spot and at the same time reducing the light intensity.
Look, you look like you're really not up to the mark to discuss this kind of subject, and I'm not here to educate you on the most basic of these things.
So we better move on from here, as this is all out of topic anyway.